Difference between revisions of "2006:Sandbox/"

Latest revision as of 19:46, 9 August 2006

$\pi ={\frac {2}{5}}{\sqrt {3}}+24\int _{0}^{1/4}{{\sqrt {x^{3}-x^{2}}}dx}$

Revision as of 16:44, 9 August 2006 (view source) CameronJones (talk \| contribs) ← Older edit		Latest revision as of 19:46, 9 August 2006 (view source) Jang (talk \| contribs)
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−	<math>\pi=\frac{2}{5} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x-x^2}dx}</math>	+	<math>\pi=\frac{2}{5} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x^3-x^2}dx}</math>